x^2-4x-12=x^2-8x+16

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Solution for x^2-4x-12=x^2-8x+16 equation: 



x^2-4x-12=x^2-8x+16

We move all terms to the left:

x^2-4x-12-(x^2-8x+16)=0

We get rid of parentheses

x^2-x^2-4x+8x-16-12=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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